A 25.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/ °C.mol) is heated 82.4 °C and dropped into a calorimeter containing water (specific heat capacity of water is 4.18 J/g.oC) initially at 22.3 °C. The final temperature of the water is 24.9 °C.Calculate the mass of water in the calorimeter.
Upon inspection, one of the given heat capacities is in J/°C mol; we will convert it to J/g°C
To solve this problem, we will assume that the heat released by the aluminum piece is the same as the heat absorbed by the water.
We have the specific heat formula
c=specific heat capacity
Δ T=change in temperature
Then we will compare both equations and consider the variables, with subindex 1 being for water and 2 for aluminum
Solving for m1, we have
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Chemistry, published 24.05.2023
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