What mass of lioh would need to be dissolved in water to make 300.0 ml of a solution with a ph of 11.71?

Answer by Guest

Answer: Mass of LiOH = (1.54 × 10⁻³ mol) × (23.9 g/mol) = 0.0368 g ==== OR: [ (1 × 10⁻¹⁴)/10⁻¹¹·⁷¹ mol OH⁻ ions / 1000 mL solution] × (300 mL solution) × (1 mol LiOH / 1 mol OH⁻ ions) × (23.9 g LiOH / 1 mol LiOH)

Explanation:

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