If the starting frequency of aa is 0.7, what is the frequency of the a allele in this starting population?

Answer by Guest

Hardy-Weinberg equilibrium state of the population, the total frequency of an allele and its alternate allele in a population is p + q = 1. Therefore the frequency of the alternate allele q in the starting  population is

q = (1 - 0.7) = 0.30.

An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic point in the population.

For example if allele frequency is 0.5 it mean , a person has a 0.5 chance of passing on one of two alleles for a given gene. If the allele frequencies of p and q is equal 1 the two alleles when combined gives the frequency  equal 100%.

To learn more about Hardy-Weinberg equilibrium , here

brainly.com/question/16823644

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