# A sprinter passes two through points that are separated by distance 50.0 m in 6.00 seconds. if his speed at the second point was 9.00 m/s and his acceleration is constant, what was his speed at the first point?

**Acceleration **is the change in velocity with regard to time, while speed is the distance traversed by the body in the amount of time required.

**8.33 **meters per second is the speed at the starting location, and the antelope accelerates at a rate of **1.1117 **meters per second squared.

### What is Acceleration ?

The distance between the two points is 70 m.

The time taken by the antelope to cover the distance between two points is 6.00 s.

Speed of the antelope when it passes the second point is 15.0 m/s.

a) Speed at the first point-

Use the equation of motion, which is,

×

Here S is the distance, t is time taken, u is initial velocity which is equal to the speed at the first point and v is velocity.

Put the values and ind the initial velocity,

70 = __u + 15__ × 6

2

u = 8.33

Hence the speed at the first point is **8.33 meter per second**.

b) Acceleration-

Us the equation of motion,

V =u + at

15 = 8.33 + a× 6

a = 1.1117

Thus the **acceleration **of the antelope is **1.1117** meter per second squared.

**Acceleration **is the rate at which velocity, both in terms of speed and direction, varies over time. When anything moves faster or slower in a straight line, it is said to have been accelerated.

The **velocity **of an object can change if it moves faster, slower, or in a different direction. The **moon **orbiting the earth, an apple falling to the ground, and a car stopping at a set of traffic lights are a few examples of acceleration.

The pace at which **displacement **varies is known as velocity. Acceleration is the change in speed that occurs quickly. Velocity is a vector quantity since it consists of both magnitude and direction.

To learn more about **Acceleration **from the given link:

#SPJ4

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Find another answersPhysics, published 10.03.2023