Which correctly describes the root of the following cubic equation? x^3-3x^2+4x-12=0
I know that the factors of 12 are 1, 2, 3, 4, 6, and 12
Therefore, the possible roots are 1, 2, 3, 4, 6, and 12
Answer:
The equation has one real root and two complex roots.
Step-by-step explanation:
The given equation is
The above equation is true form x=3, therefore (x-3) is a factor of above equation.
Use long division or synthetic division method to divide the equation by (x-3).
Equate each factor equal to zero.
Therefore 3 is a real root of the equation.
2i and -2i are complex roots of the equation.
Therefore the equation has one real root and two complex roots.
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