Please im failing math and this is an extra credit problem.

Answer by Guest

Answer:

  1:30 pm

Step-by-step explanation:

You want the time when Sahil catches up to Joaquin, who left at 8 am riding 50 mph when Sahil left at 8:30 am, riding at 55 mph.

Time, Speed, Distance

The relation between time, speed, and distance is ...

  distance = speed × time

  time = distance / speed

Joaquin has a head start of 0.5 hours (30 minutes), during which time he traveled ...

  head start distance = (50 mi/h) × (0.5 h) = 25 mi

Sahil is traveling 55 - 50 = 5 mph faster than Joaquin, so closes that gap at the rate of 5 mi/h. The time it takes to close the gap entirely is ...

  time = distance / speed = 25 mi / (5 mi/h) = 5 h

So, 5 hours after Sahil starts at 8:30, the two riders will be at the same place.

Sahil catches Joaquin at 1:30 pm.

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Additional comment

By the time the gap is closed at 1:30 pm, both riders will have traveled a distance of ...

  distance = speed × time = 50 mi/h × 5.5 h = 55 mi/h × 5 h = 275 mi

In the attached graph, we have written equations for the total distance traveled by each motorcycle. The x-value used is the clock time on a 24-hour clock. That is, their meeting time of 13.5 hours corresponds to 13:30 hours or 1:30 p.m. on a 12-hour clock.

Answer by Guest

No no no no no no he left after him he’s not catching up

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