**\sqrt(4x)=x-3, what are all values of x that satisfy the given equation?**

I.1

II. 9

I.1

II. 9

**Answer:**

1 and 9

**Explanation:**

Taking Square on both sides:

(sqrt(4x))^2= (x-3)^2

4x= x^2 + 9 - 6x

x^2 - 10x + 9= 0

Solving Quadratic Equation

x^2 -9x -1x +9=0

x(x-9) -1(x-9)=0

(x-1)(x-9)=0

x=1 x=9

Rate answer

If your question is not fully disclosed, then try using the search on the site and find other answers on the subject SAT.

Find another answers