**Provide an appropriate response.**39) Find a set of 7 scores that has the same mean but a smaller standard deviation than the

set {65, 71, 77, 80, 82, 90, 96}.

You don't even have to look up the definition of 'standard deviation'. You only

have to remember that 'smaller standard deviation' means 'less spread-out'.

First, let's find the mean (average). It's not supposed to change:

1/7th of (65 + 71 + 77 + 80 + 82 + 90 + 96) = 561/7 = ** 80 and 1/7** .

Now, just pick 7 scores that total 561 and are all bunched up.

The easiest way would be 80, 80, 80, 80, 80, 80, 81 .

But that's so easy that it feels like cheating.

Let's say

**.**

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