7. How many solutions are there for 5^2+7x-4=0

Answer:

Step-by-step explanation:

This is a polynomial of degree 2 and has 2 solutions.

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The equation 5^2+7x-4=0 has only one solution

Solution:

Given, equation is $5^{2}+7 x-4=0$

We have to find the number of solution that the given equation can have.

Now let us solve the given equation to find the number of solutions it has.

So, take the equation $5^{2}+7 x-4=0$

On squaring 5 we get 25

25 + 7x – 4 = 0

7x + 25 – 4 = 0

Adding 25 and -4 we get,

7x + 21 = 0

7x = - 21

x = - 3

Here we got only one value for "x"

Hence, the given equation has only one solution and that is x = – 3

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