At 650 mm hg a gas has a volume of 190 l what is its volume at standard pressure


Answer:Volume occupied by the gas at standard pressure is 162.5 L.

Explanation:

Pressure of the gas when it occupies volume of 190 L = 650 mmHg

Volume occupied by the gas when the gas is at standard pressure.

The value of standard pressure = 1 atm = 760 mmHg

P_1=650 mmHg,V_1=190 L,P_2=760 mmHg,V_2=?

According to Boyle's Law: Pressure\propto \frac{1}{Volume} (at constant temperature)

P_1\times V_1=P_2\times V_2

V_2=\frac{P_1\times V_1}{P_2}=\frac{650 mmHg\times 190 L}{760 mmHg}=162.5 L

Volume occupied by the gas at standard pressure is 162.5 L.


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