What is the percent composition of copper in copper (II) hydroxide (Cu(OH)2 )? Question 7 options: a) 65.13 % Cu b) 32.80 % Cu c) 97.57 % Cu d) 2.07 % Cu


Answer:

The answer to your question is letter a. 65.13%

Explanation:

Percent composition of Copper in Cu(OH)₂

Process

1.- Calculate the molecular weight of Copper hydroxide

Cu(OH)₂ = 64 + (16 x 2) + (2 x 1)

              = 64 + 32 + 2

              = 98 g

2.- Solve the problem using proportions

                       98 g of Cu(OH)₂  ---------------  100 %

                       64 g of Cu           ----------------   x

                           x = (64 x 100) / 98

                           x = 6400 / 98

                           x = 65.2 %


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